Tension in String for 0.25 kg Ball Revolving at 2 Hz

  • Thread starter Alexs45
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In summary, the conversation discusses the calculation of tension in a rotating ball attached to a string. The formula T (tension) = m*(v^2)/R is mentioned, along with the use of velocity (v) and frequency to find the speed. The importance of representing velocity through frequency is also highlighted. The conversation ends with a request for a step-by-step example of the problem.
  • #1
Alexs45
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A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m. If the ball revolves twice every second, what is the tension in the string?
 
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  • #2
Whyy

Why Wont Anoyboyd Help Me!
 
  • #3
T (tension)= m*(v^2)/R
And v (speed) You can find from frequency!?
 
  • #5
so do you just plug the numbers into that formula and if it revolves twice every second does that effect the problem.
 
  • #6
You should represent velocity throgh the frequency
Or You can find velocity through v=s/t
 
  • #7
do you mind doing out the problem because i am confused.like a step by step example..thank you so much Yegor
 
  • #8
1.The tension in the rope/wire is a centripetal force.Which formula giving the centripetal force would be best to use in this case?

Daniel.
 

1. What is the formula for calculating tension in a string?

The formula for calculating tension in a string is T = (m*v^2)/r, where T is tension, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular motion.

2. How do you determine the mass of the object in the given scenario?

In this scenario, the mass of the object is given as 0.25 kg.

3. Can you explain the significance of 2 Hz in the given scenario?

The value of 2 Hz represents the frequency at which the ball is revolving, which is the number of revolutions per second. It is an important factor in calculating tension in a string as it affects the velocity of the object in the formula.

4. How does the radius of the circular motion affect the tension in the string?

The radius of the circular motion is directly proportional to tension in the string. This means that as the radius increases, the tension in the string also increases.

5. Is tension in the string the only force acting on the object in this scenario?

No, there may be other forces acting on the object such as gravity or friction. However, the formula for tension in a string only takes into account the centripetal force required to keep the object in circular motion.

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