AP PHYSICS ~ FLUIDS ~ A cube of osmium with a volume of

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A cube of osmium with a volume of 166 cm³ is placed in fresh water, resulting in an apparent weight of 35.0 N. The calculated density of osmium is 21506 kg/m³, derived from converting the weight to mass and dividing by the volume. There was confusion regarding the conversion of volume from cm³ to m³, with one participant mistakenly stating it was 1.66 m³ instead of the correct 0.000166 m³. The relevance of Archimedes' principle was questioned, as the cube's placement in water should affect buoyancy calculations. Ultimately, the discussion highlighted the importance of accurate unit conversions in density calculations.
Silverbolt
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A cube of osmium with a volume of 166 cm³ is placed in fresh water. The cube's apparent weight is 35.0 N. What is the density of osmium?This is what I did:

I converted force to mass by : 35 N / 9.8 = 3.57 kg

then changed the 166 cm³ to m³ which is : .000166 m³

After that i divided the mass and the volume: (3.57 kg)/(.000166 m³)

And so I got the density as 21506 kg/m³
PLEASE HELP ME IF I'M WRONG
 
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What did you do with the Archimedes principle/force ?
 
Your conversion from cm^3 to m^3 was off, it's actually 1.66m^3, you move it two decimal places to the left.
 
Silverbolt said:
then changed the 166 cm³ to m³ which is : .000166 m³

That is correct, and iilego's post #3 is wrong.

The question says "the cube was placed in fresh water". You haven't used that information anywhere. What difference does it make if the cube is in water or in air?
 
cm equals .01 meters, which is two decimal places to the left, am I wrong? I never mentioned anything about the answer, just that his conversion was off on the volume.
 
If 1 cm = 0.01 m, then (1 cm)^3 = 1 cm^3 = (0.01 m)^3 = 10^(-6) m^3

1m^3 is rather a large volume
 
never mind, I was wrong, the conversion was right, sorry :(
 

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