AP Physics Lab: Coefficient of Friction

AI Thread Summary
The discussion centers on a student's request for assistance with calculating the coefficient of friction from a physics lab experiment involving a car on an inclined rail. The setup includes a pulley system with a hanging mass that affects the car's motion down the incline. The student provides specific measurements, including the weight of the car and various angles, but is struggling with the calculations, resulting in unexpectedly large values for the coefficient of friction. The equation provided relates to the forces acting on the car and the hanging mass, but the student seeks clarification on its application. Overall, the student is looking for guidance on how to correctly calculate the coefficient of friction based on their experimental data.
gothicpie
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Hi, I'm new to this forum and I hope I can find some help with my AP Physics class! I find the subject really interesting, I just have a hard time applying it. Also, I don't really know the people in my AP Physics class, so it would be awkward to ask them for help.

Anyway, last week we did this Lab to find the Coefficient of Friction. I have the data and need help on how to find the coefficient of friction.

The lab goes as follows: We have a car and rail set up a certain degree. At the end of the rail there is a photogate, and we tape a ruler on the top of the car (so that it passes through the photogate). At the top of the rail there is a pulley, and a string that goes through it. One end of the string is attached to the car, and the other end to a certain mass. We are supposed to calculate the friction between the car and the rail.

The information that I have is the weight of the car (.348kg), the width of the ruler that was taped onto the car (.025m), and 4 sets of angles, masses, and times. (For example, the rail was set up at a 43 degree angle and the mass on the other end of the string from the car weighed .0994 kg. The cart took .018 seconds to go through the photogate 9 times, and .017 twice.)

Now, I've got this equation from a lab partner, but I keep getting really big numbers for the coefficient. (The equation is: acceleration times the total mass equals mass of the cart times sin theta minus the mass hanging from the string times gravity minus mu (coefficient of friction) times mass of the cart times gravity times cosine theta... a(tm) = (m1 sine theta - mass2 g) - mu(m1 g cosine theta)...). The "m1 g sine theta" is the equation for the downhill force.

I hope this is enough information for someone to help me. If possible, maybe someone could figure out a coefficient for me and explain while they're doing it, how? Thank you for your time.
 
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Let me see if I have this right. A free falling mass over a pulley or something is pulling the car up an incline ?
 
Let me see if I have this right. A free falling mass over a pulley or something is pulling the car up an incline ?

The car is going down the incline, and there is a string attached to the car which goes over the pulley and has a weight attached to it.

Like this: http://img.photobucket.com/albums/v285/gothicpie/physicslabfriction.jpg
 
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I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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