AP Physics Multiple Choice Question

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A force of 12 N applied tangentially to a wheel with a radius of 0.70 m and a rotational inertia of 3.0 kg-m2 results in an angular acceleration of 2.8 rad/s². The kinetic energy of the wheel after the force acts for 20 seconds needs to be calculated using the formula K=1/2Iw². There was confusion regarding the calculation of angular velocity, where it was clarified that multiplying acceleration by time is necessary to find the correct velocity. The discussion highlights the importance of understanding the relationship between angular acceleration and time in rotational motion. Overall, the calculations and concepts discussed are crucial for solving physics problems related to rotational dynamics.
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5. A force of 12 N is applied tangentially to the rim of a wheel with radius 0.70 m and rotational inertia 3.0 kg-m2. What angular acceleration results?
a) 2.6 rad/s2 b) 2.8 rad/s2 c) 3.2 rad/s2 d) 3.4 rad/s2 e) none of these
____6. If the force in question #5 acts for 20 s, what will be the kinetic energy of the spinning wheel?
a) 4.7 x 103 j b) 4.4 x 102 j c) 4. 7 x 10 j d) 84 j e) none of the above answers is within 10 % of the correct value

I figured out number 5 to be B.) 2.8 rad/s by rF/I from Torque=Ia
For 6, when I solve using K=1/2Iw^2, and using 2.8 rad/s^2 divided by 20 seconds to get the angular velocity of .14 rad/s, I get a really small number, like .03. What am I doing wrong?
 
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girlphysics said:
5. A force of 12 N is applied tangentially to the rim of a wheel with radius 0.70 m and rotational inertia 3.0 kg-m2. What angular acceleration results?
a) 2.6 rad/s2 b) 2.8 rad/s2 c) 3.2 rad/s2 d) 3.4 rad/s2 e) none of these
____6. If the force in question #5 acts for 20 s, what will be the kinetic energy of the spinning wheel?
a) 4.7 x 103 j b) 4.4 x 102 j c) 4. 7 x 10 j d) 84 j e) none of the above answers is within 10 % of the correct value

I figured out number 5 to be B.) 2.8 rad/s by rF/I from Torque=Ia
For 6, when I solve using K=1/2Iw^2, and using 2.8 rad/s^2 divided by 20 seconds to get the angular velocity of .14 rad/s, I get a really small number, like .03. What am I doing wrong?

Suppose this was a regular linear kinematics problem where you have an acceleration a and you want to find the velocity v after some time t, what's the formula?
 
gneill said:
Suppose this was a regular linear kinematics problem where you have an acceleration a and you want to find the velocity v after some time t, what's the formula?

you can't divide acceleration/time to get velocity?
 
girlphysics said:
you can't divide acceleration/time to get velocity?

Nope. What would the resulting units be?
 
(rad/s^2 )/ s
so rad/s which is velocity?
I don't know something in my brain isn't connecting
 
gneill said:
Nope. What would the resulting units be?

No it would be rad/s^3. duh omg
 
girlphysics said:
No it would be rad/s^3. duh omg

:smile:

So, better to multiply acceleration by time then... :wink:
 
thank you! I got A I hope its right!
 
girlphysics said:
thank you! I got A I hope its right!

Looks good.
 
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