Application of the ideal gas law

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SUMMARY

The forum discussion centers on calculating the amount of liquid nitrogen (LN2) required to achieve a pressure of 10.1 bar in a 66 m³ vessel, assuming an isothermal process at 300 K. The initial calculation estimates approximately 27,000 moles of nitrogen, leading to a total mass of 378 kg and a volume of 468 liters based on the density of LN2 at boiling temperature (0.808 kg/L). However, a critical error is identified regarding the molar mass of nitrogen, which is 28 g/mol, not 14.0067 g/mol, necessitating a revision of the calculations.

PREREQUISITES
  • Understanding of the Ideal Gas Law
  • Knowledge of molar mass and density calculations
  • Basic principles of thermodynamics, specifically isothermal processes
  • Familiarity with liquid nitrogen properties
NEXT STEPS
  • Review the Ideal Gas Law and its applications in real-world scenarios
  • Learn about the properties of nitrogen, including its molar mass and phase changes
  • Study isothermal processes and their implications in gas behavior
  • Explore practical applications of liquid nitrogen in industrial settings
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Students in chemistry or engineering, professionals in thermodynamics, and anyone involved in cryogenics or gas calculations will benefit from this discussion.

doktorglas
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Hi,

I want to calculate the amount of liquid nitrogen (at boiling temp.) needed to build a pressure of 10.1 bar in a vessel of volume 66 m3. The liquid will be poured slowly into the vessel, boil off and fill the volume with gas at the specified pressure. I make the assumption that the process is isothermal (T = 300 K); is this a valid assumption? If so, the ideal gas law gives that the needed amount of N2 is n ≈ 27000 moles.

Given that the molar mass is m = 14.0067 g/mol, we get a total mass of M = 378 kg. The density of liquid nitrogen at boiling temp. is 0.808 kg/l, so this gives the needed amount 468 liters.

Is this reasonable, or are there any major flaws in the calculation?

Thanks
 
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The assumption might be valid for a homework problem. It's hard (not impossible) to imagine a physical situation where there was sufficient heat to boil the LN2 and not also heat the gas. There is also a major flaw - check your molar mass.
 
J.L.A.N. said:
Hi,

I want to calculate the amount of liquid nitrogen (at boiling temp.) needed to build a pressure of 10.1 bar in a vessel of volume 66 m3. The liquid will be poured slowly into the vessel, boil off and fill the volume with gas at the specified pressure. I make the assumption that the process is isothermal (T = 300 K); is this a valid assumption? If so, the ideal gas law gives that the needed amount of N2 is n ≈ 27000 moles.

Given that the molar mass is m = 14.0067 g/mol, we get a total mass of M = 378 kg. The density of liquid nitrogen at boiling temp. is 0.808 kg/l, so this gives the needed amount 468 liters.

Is this reasonable, or are there any major flaws in the calculation?

Thanks
Isn't the molar mass of N2 28 g/mole?
 

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