Applying the Trapezoidal Rule for f(t)=t^2 with deltaT=0.5

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juice34

Homework Statement



f(t)=t^2 and \Deltat=.5, where 0<=t<=2 what is the closest? 4, 2.75, 2.67, or 1.33

Homework Equations


deltaT=(a-b)/n

and the formula for the trapezoidal rule when n>1


The Attempt at a Solution



I get n=4 therefore the final answer I get a total area under the function is 5. Does that make sense.
 
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The final answer is wholly dependent on the number of trapezoids chosen, and in this case is 4.
 
Actually I just got it, 2.75 is the answer and if anyone is wondering this is a FE exam question.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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