Arc Length (Set up the Integral)

johnhuntsman
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x = t + cot t
y = t - sin t
0 ≤ t ≤ 2π

Somehow the answer is:


∫sqrt(3 - 2*sin t - 2*cos t) dt
0

I'm afraid I don't know where to start on this one. I don't need someone to walk me through it (probably) but a point in the right direction would be appreciated.
 
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Nevermind this post everyone. I made a foolish mistake. I'm supposed to do sqrt[(x')^2 + (y')^2] for anyone who makes the same mistake and comes across this in a Google search. It was in an earlie rpart of the chapter I'm working on even. Sorry everyone.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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