Archimedes Principle and Buoyancy

AI Thread Summary
When a 100g object with a density less than water is submerged in a beaker of water on a triple beam balance, the measured weight will equal the combined weight of the water, the beaker, and the object. The buoyant force acting on the object does not affect the balance reading, as the balance measures the total weight of the system. Newton's third law supports this, indicating that the forces are equal and opposite, thus not altering the overall weight measured. The confusion arises from misunderstanding how buoyancy interacts with weight measurement in a closed system. Overall, the balance reflects the total weight regardless of the buoyant force acting on the submerged object.
Lisas941
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Homework Statement


A 100g object having a density less than that of water is placed into a beaker half full of water. The beaker is then placed on a triple beam balance. Would be measured weight be equal to, greater than, or less than the weights of the water, the beaker, and the object added together? Explain.

Homework Equations


Fb = ρVg = mf g
Wapt = mg - Fb

The Attempt at a Solution


Would it be equal to as the balance isn't affected by the buoyant force within the beaker? I'm confused.
 
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your attempt is reasonable enough, but Newton's third law would be helpful.
 
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