Are Carbon-Oxygen Double Bonds More Stable Than Single Bonds?

AI Thread Summary
A carbon-oxygen double bond is more thermodynamically stable than a single bond due to the increased overlap of p-orbitals, which leads to stronger bonding interactions. The discussion raises questions about the stability comparison of these bonds in specific contexts, such as with RRC+-O- or R-CH2-OH. Additionally, the -OH group is generally not considered a good leaving group in basic conditions, as it requires protonation to facilitate leaving, which contradicts the nature of basic environments. The conversation emphasizes the need for clarity on the conditions under which these reactions occur. Understanding these concepts is crucial for organic chemistry applications.
SublimeGD
Messages
12
Reaction score
0
2 quick ochem questions...

1. Why is a carbon oxygen double bond more thermodynamically stable than a carbon oxygen single bond?

2. Can -OH be a leaving group in basic conditions, it would seem strange to protinate it in basic conditions?

Thanks!
 
Physics news on Phys.org
SublimeGD said:
2 quick ochem questions...

1. Why is a carbon oxygen double bond more thermodynamically stable than a carbon oxygen single bond?

2. Can -OH be a leaving group in basic conditions, it would seem strange to protinate it in basic conditions?

Thanks!

More thermodynamically stable than what? Than RRC+-O-? Or R-CH2-OH?

OH is never a good leaving group unless the negative charge is somehow dealt with. In what base catalyzed reaction do you see OH- as a leaving group?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top