Are Newton's Laws Applicable to Component Forces and Resultant Acceleration?

AI Thread Summary
Newton's laws are applicable to component forces and resultant acceleration, as all forces can be resolved into components along chosen axes. When analyzing forces, the sum of forces in each direction can be set to zero, leading to the conclusion that the overall force can be expressed as Ʃf=ma. Component vectors contribute to acceleration, and vector addition or subtraction yields the resultant acceleration. Therefore, the principles of Newton's laws hold true when dealing with forces in component form. Understanding this relationship is crucial for solving physics problems involving forces and motion.
Mdhiggenz
Messages
324
Reaction score
1

Homework Statement



I just wanted to know if I was correct, when dealing with a Newton law problem that has components.

Ʃfx=0 and ƩfY = zero

However when we add the forces together then we can use Ʃf=ma

thanks




Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
1. All forces can be resolved into components whatever axis you choose.
2. Component vectors also produce acceleration. Vector addition or subtraction produces the resultant acceleration.

Thus it is applicable, f=ma for components or resultant forces.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Explanation for Newton II giving negative mass in my Physics lab results please
Replies
44
Views
3K
Proving Newton's 3rd law from conservation of momentum
Replies
2
Views
681
Rocket acceleration problem: confused about Newton's 2nd Law
Replies
42
Views
5K
Why doesn't Newtons third law also apply to the frame?
Replies
2
Views
2K
Having a hard time learning Newton's 2nd law
Replies
5
Views
2K
Rank forces according to magnitude: Newton's 2nd/3rd laws
Replies
5
Views
7K
Problem of spring block system: force vs conservation of energy
Replies
20
Views
3K
Explain speed limits on curved ramp with Newton's Laws
Replies
3
Views
2K
Newton's 2nd law with oscilations
Replies
17
Views
2K

Hot Threads

Recent Insights

Back
Top