Are These Photon Wavelength and Linear Momentum Calculations Correct?

[mss90]

Homework Statement

I had to find wavelenght and linear momenta of fotons with energies of 3eV, 50 KeV and 1.0 MeV

Are these correct?

Homework Equations

E=hc/λóλ=hc/E and p= h/ λ

The Attempt at a Solution

a. 3eV Hence λ=(6.63E-34*3E8)/3=6.63E-26m
p = 6.63E-34/6.63E-26 = 1E-8
b. 50 KeV = 50000 eVλ=(6.63E-34*3E8)/ 50000 =3.978E-30m
p = 6.63E-34/3.978E-30 = 1.66E-4
c. 1.0 MeV = 1 000000 eVλ=(6.63E-34*3E8)/ 1 000000 = 1.989E-31m
p = 6.63E-34/1.989E-31 = 0.0033
[/B]

 

[collinsmark]

Hello mss90,

Welcome to PF! :)

Don't forget to first convert the energy (given in units of eV, keV, and MeV) to units of Joules first, before plugging in the numbers.

 

[mss90]

Alright, can you confirm that this is correct:

3eV * 1.60E-19 = 4.8E-19 J Hence λ=(6.63E-34*3E8)/4.8E-19=4.17E-7m = 0.417µm
p = 6.63E-34/4.17E-7= 1.59E-27

 

[collinsmark]

Alright, can you confirm that this is correct:

3eV * 1.60E-19 = 4.8E-19 J Hence λ=(6.63E-34*3E8)/4.8E-19=4.17E-7m = 0.417µm
p = 6.63E-34/4.17E-7= 1.59E-27

That looks about right, although there might be some rounding errors going on somewhere.

By the way, when calculating the photons' momentum magnitude, you can simply use the p = \frac{E}{c} formula (after converting the energy into units of Joules, simply divide that by the speed of light, 3 × 10⁸ m/s, and you have the magnitude of the photon's momentum. That way you don't need to depend on the λ intermediate step as part of the answer).