Area and volume calculation (no integration))

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The discussion focuses on calculating areas and volumes without using integration. The area of a rectangle can be computed using the product of Δx and Δy, while the area of a wedge in polar coordinates can be derived using the difference of areas of circles and an angle ratio. For volume, the parallelepiped's volume is calculated as ΔxΔyΔz, and a similar approach is suggested for spherical coordinates using Δρ, Δφ, and Δθ. The conversation references the ancient Greeks' method of exhaustion as a precursor to calculus for deriving these formulas algebraically. Understanding these concepts allows for area and volume calculations in various coordinate systems without integration.
Jhenrique
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I can compute the area of the rectangle formed by Δx and Δy simply by product ΔxΔy.
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Now, how can I to compute the area in gray given Δr and Δθ?
image.png


Also, I can to compute the volume of a parallelepiped formed by Δx, Δy and Δz, simply multiplicand ΔxΔyΔz. But, how can I compute the volume in shpherical coordinates formed by Δρ, Δφ and Δθ?

Convention:
image.jpg
 
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If you know the radius then you can compute the wedge by computing the area of circles r and r+dr and an angle ratio dtheta/(2*pi) for dtheta measured in radians:

area(wedge) = area(circle(r+dr) - area(circle(r)) * (dtheta / 2*pi)

In spherical coordinates you have a more complicated situation where you could derive a formula for the 3D wedge using calculus.

If you're thinking the ancient greeks didn't know calculus so how did they algebraically arrive at the answer then
you need to read about their calculus precursor the method of exhaustion:

http://en.wikipedia.org/wiki/Method_of_exhaustion

http://www.math.ubc.ca/~cass/courses/m446-03/exhaustion.pdf

http://www-groups.dcs.st-and.ac.uk/history/HistTopics/The_rise_of_calculus.html
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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