- #1
hamburgler
- 22
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I would appreciate any help on this problem because I am completely confused.
1. The problem statement...
What is the area enclosed by one petal of the rose r=6cos3[tex]\theta[/tex]?
(w/o a calc)2. The sorry attempt...
(1/2)[tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]
and the integral is from [tex]\pi[/tex] to [tex]\pi[/tex]/3
I'm pretty sure that's how you set it up, but I saw other people doing it another way.
So then [tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]
and then I get stuck at the integral of the function...
1. The problem statement...
What is the area enclosed by one petal of the rose r=6cos3[tex]\theta[/tex]?
(w/o a calc)2. The sorry attempt...
(1/2)[tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]
and the integral is from [tex]\pi[/tex] to [tex]\pi[/tex]/3
I'm pretty sure that's how you set it up, but I saw other people doing it another way.
So then [tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]
and then I get stuck at the integral of the function...
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