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I would appreciate any help on this problem because I am completely confused.

What is the area enclosed by one petal of the rose r=6cos3[tex]\theta[/tex]?

(w/o a calc)

(1/2)[tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]

and the integral is from [tex]\pi[/tex] to [tex]\pi[/tex]/3

I'm pretty sure that's how you set it up, but I saw other people doing it another way.

So then [tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]

and then I get stuck at the integral of the function...

**1. The problem statement...**What is the area enclosed by one petal of the rose r=6cos3[tex]\theta[/tex]?

(w/o a calc)

**2. The sorry attempt...**(1/2)[tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]

and the integral is from [tex]\pi[/tex] to [tex]\pi[/tex]/3

I'm pretty sure that's how you set it up, but I saw other people doing it another way.

So then [tex]\int[/tex](6cos3[tex]\theta[/tex])^2d[tex]\theta[/tex]

and then I get stuck at the integral of the function...

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