Area under v vs t sinusoidal trace

[lavster]

if I have a sinusoidal trace on an oscilloscope (v vs t) and I wanted to find the area under the wave form squared graph I could integrate the sqaured waveform with respect to t.

but since i don't have the integration facility... is it fair to say that the area under the graph is proprtional to vrms^2 ?

im confused to what vrms is? the average v^2 value (i know its Vpeak/2)

thanks

 

[davenn]

wiki has a pretty good article on rms

basically its 0.707 of the peak value
and from what I remember the rms power of an AC circuit ( average power) is the equivalent to the DC power
( did that make sense ?)

Dave

 

[alva]

im confused to what vrms is? the average v^2 value (i know its Vpeak/2)
thanks

An AC voltage of 10 volts rms ( no matter whether it is sinusoidal or not ) means that this AC voltage will heat up a resistor as a DC voltage of 10 volts.

Remember that the power transformed into heat is V^2 / R.

basically its 0.707 of the peak value

in a sinusoidal wave.

.. is it fair to say that the area under the graph is proprtional to vrms^2 ?

No, it is proportional to Vrms an also proportional to Vpeak ( because it is a sinuoidal wave ).