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Atomic energy levels Silicon

  1. Jan 12, 2015 #1
    1. The problem statement, all variables and given/known data
    Silicon has the configuration [Mg] ##3p^2##.
    Explain why there are more L, S, J levels for the ##3p4p## configuration
    than in the ##3p^2## configuration.

    2. Relevant equations


    3. The attempt at a solution
    My thought is because in the ##3p^2## subshell you have less variations of ##M_l## and ##M_s## because both electrons cannot have the same quantum numbers, wheres with the ##3p4p## level, they could both have ##M_l=+1## and ##M_s=+1## because the ##n## the principle quantum number is different?
     
    Last edited: Jan 12, 2015
  2. jcsd
  3. Jan 12, 2015 #2

    DrClaude

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    Staff: Mentor

    You're on the right track. But there are more states than just the one you cited (##M_l=+1## and ##M_s=+1##).
     
  4. Jan 13, 2015 #3
    Yes, i understand that there would twice (?) as many states in the excited level because the electrons would be free to have any ##m_l## or ##m_s##, but the states for the ##3p^2## level are restricted by the Pauli principle.
     
  5. Jan 13, 2015 #4

    DrClaude

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    Staff: Mentor

    Not twice, because it is only the states where the two electrons have the same spin in the same orbital that have to be discarted. But I think you get the idea.
     
  6. Jan 13, 2015 #5
    Ah okay thankyou!
     
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