Atwood Machine: Find m1's Descent and Velocity

AI Thread Summary
In the Atwood machine problem, m1 (2.00 kg) and m2 (7.50 kg) are analyzed with negligible pulley and string mass. To determine m1's descent and velocity, the acceleration can be calculated using the equation a = (g * (m2 - m1)) / (m1 + m2). For part (a), the distance m1 descends can be found using the kinematic equation vf^2 = vi^2 + 2ad. The discussion highlights the need for force diagrams to derive equations for both masses and suggests an energy approach as an alternative method. The second part of the problem regarding m1's velocity after 1.80 seconds remains under discussion.
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Homework Statement


In the Atwood machine shown below, m1 = 2.00 kg and m2 = 7.50 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.80 m/s downward.
(a) How far will m1 descend below its initial level?

(b) Find the velocity of m1 after 1.80 s.

Homework Equations


f= ma
vf^2 = v^2 + 2ad

The Attempt at a Solution


i think for part a u use the equation i put above..but i don't know how to figure out acceleration...but i think its splitted between the two objects
 
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Hi physics_geek,

physics_geek said:

Homework Statement


In the Atwood machine shown below, m1 = 2.00 kg and m2 = 7.50 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.80 m/s downward.
(a) How far will m1 descend below its initial level?

(b) Find the velocity of m1 after 1.80 s.

Homework Equations


f= ma
vf^2 = v^2 + 2ad

The Attempt at a Solution


i think for part a u use the equation i put above..but i don't know how to figure out acceleration...but i think its splitted between the two objects


To find the acceleration, start by drawing force diagrams for each of the objects. Using \sum F = m a for each of the diagrams then gives two equations with two unknowns.

(You can also use an energy appoach here.)
 
Use the formula a= (gm1 + gm2)/(m2+m1) to find the acceleration then use the formula V^2=-2ad to find the distance. Bada bing bada boom!
Im still workin on the second part unfortunately...
 
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