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**1. Homework Statement**

I know how to do this type of problem, I'm just confused as to how to determine the distance the (4m) mass goes up .

**2. Homework Equations**

N/A

**3. The Attempt at a Solution**

So I was thinking that if mass (5m) and mass (3m) go in opposite directions then mass (4m) will remain where it is. If mass (5m) and mass (3m) both go down the same distance (x=y), then mass (4m) will go up x or y. But what if x≠y? I was tried to have both mass (5m) and mass (3m) go down so that mass (4m) can go up. I figured if mass (5m) goes down by -2x, then mass (3m) goes up by 2x = y which would still have mass (4m) where it is. So then I thought about moving mass (5m) down another -4x so in total -6x but also have mass (3m) go down -4x = -y so then mass (4m) goes up 4x. I don't know if that makes sense, but this whole thing is confusing me.