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My question is about the Atwood machine.

There are two blocks of same weight (M) suspended on a rope of each side of a pulley. There is a squared plaque (weight = m) placed on one of the blocks. When the block is dropped, is accelerates on a distance H until the squared plaque is stopped by a ring, but the block underneath continues it way at a constant speed. The distance D traveled by the block at constant speed, after the plaque is stopped by the ring, lasts "t" seconds. Prove that gravity acceleration, "g", is represented by the formula:

g = ((2M + m)D^2) / (2mHt^2)

Help for this question would be really, really apprecied...thank you !

Christopher