How Is Average Force Calculated in Physics Problems?

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The discussion focuses on calculating average force in a physics problem involving a ball's motion. The user has determined the distance traveled by the ball in the first 0.40 seconds to be 0.8 meters and calculated the change in momentum as 0.19 Ns. However, they question the discrepancy between their momentum calculation and the textbook's answer of 0.35 Ns. Clarification is sought regarding the timing of the ball's contact with the surface as indicated in the provided diagram. The conversation emphasizes understanding the relationship between distance, momentum, and force in physics problems.
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Homework Statement


http://img100.imageshack.us/img100/1867/physicsp25wz8.png

Use data from Figure to determine,
(a) the distance traveled by the ball during the first 0.40s,
(b) the change in momentum of the ball, of mass 45g, during contact of the ball with the surface,
(c) the average force acting on the ball during contact with the surface.

Homework Equations



The Attempt at a Solution


(a) 0.8m
(b) Change \ in \ momentum = mv - mu
= (45 \times 10^{-3} \times 4.2) - (45 \times 10^{-3} \times 0)
= 0.19Ns

Answer in textbook is 0.35Ns, where did I go wrong?
 
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Where on the diagram does contact with the surface begin and end?
 

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