Average rate of energy transfer & rate of energy dissipation.

AI Thread Summary
To calculate the average rate of energy transfer into gravitational potential energy for a 70kg boy running up 10 meters in 8 seconds, the relevant equation is mgh/t, which results in energy measured in joules per second (J/s). For the car, which has a mass of 700kg and decelerates from 20 m/s to rest in 5 seconds, the rate of energy dissipation requires using the kinetic energy formula, specifically 1/2mv^2/t. Participants emphasize the importance of including time in the calculations to express the rates correctly. The discussion highlights the need to differentiate between vertical energy changes and kinetic energy when applying formulas. Understanding these concepts is crucial for solving the problems effectively.
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Homework Statement


1.) A 70kg boy runs as fast as he can up a flight of stairs which has vertical height of 10metres. He achieves this in 8 seconds. Calculate the average rate of energy transfer into gravitational potential energy that must have occured.

2.) A700kg car traveling at 20ms-1 breaks to rest in 5 seconds. Calculate the rate of energy dissipation the car must achieve.

Hello, i am not certain how to calculate these.
 
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Hello,

i thought maybe mgh and mgh/t?

70x9.8x10?

700x9.8x(20)/5
 
Last edited:
E=mgh only works for vertical changes. You will use it in the first one, but not in the second one.

If I understand the question, you almost have the first one. However, it asks for the rate, which implies a time. So, you have to put the answer in the form J/s.

The second one requires a different formula, one which uses kinetic energy. See if you can find this formula; there's a handy little sticky with some of the more common formulas at the top of this page.
 
Vidatu said:
E=mgh only works for vertical changes. You will use it in the first one, but not in the second one.

If I understand the question, you almost have the first one. However, it asks for the rate, which implies a time. So, you have to put the answer in the form J/s.

The second one requires a different formula, one which uses kinetic energy. See if you can find this formula; there's a handy little sticky with some of the more common formulas at the top of this page.

Hello,

1/2mv^2/t

?
 
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