Average Translational Kinetic Energy of 1 Molecule: Solve for N

[yankees26an]

Homework Statement

1.2 x10^23 molecules of a monatomic ideal gas occupies the volume of 0.63 m3 at
atmospheric pressure. Find the average translational kinetic energy of one molecule.

Homework Equations

PV = NRT

K = 3/2*kB*T

The Attempt at a Solution

T = PV/NR

But.. what's N(moles)?

 

[ideasrule]

One mole of anything = 6.03*10^23 molecules of that thing. BTW, you can also use PV=nkT. That way, you can directly plug in 1.2 x10^23 into "n".

 

[denverdoc]

In this equation usually moles: here 1.2/6.02= n. The 10^23 on top and bottom cancel.

 

[yankees26an]

Ok so I get T = 39425 K :S

 

[ideasrule]

That's correct, although not realistic. 1.2*10^23 of a room-temperature gas would take up around 5 L.