Balanced star connected circuit measurements

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SUMMARY

The discussion focuses on measuring electrical parameters in a balanced star connected circuit. Key measurements include phase and line voltages (VP = 150V, VL = 265V), line current (IL = 2.5A), and neutral current (IN = 0A). The total power dissipated in the load is calculated as P = P1 + P2 = 1290W, with both P1 and P2 being 645W. The discussion concludes that since the circuit is purely resistive, the reactive power (Q) is 0 VAR, indicating no power factor.

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  • Experience with measuring instruments for voltage and current
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  • Study the principles of balanced three-phase systems
  • Learn about power factor correction techniques
  • Explore the implications of reactive power in AC circuits
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Steve Collins
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Measure phase and line voltages.
Measure currents in the three lines and neutral.
Measure total power dissipated in the load.
Calculate total apparent power absorbed by the load.
Determine power factor.
Draw phasor showing voltages and currents.P=P1 + P2

Q = √3(P2 - P1)

|S| = √(P2+Q2)

θ = tan-1(Q/P)Measurements taken

VP = 150V

VL = 265V

IL = 2.5A

IN = 0A

P1 = 645W

P2 = 645W

So,

P = 645 + 645 = 1290W

Q=√3(645 - 645) = 0 VAR ?
 
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After a brisk walk to the shops in the snow I have realized that this is a purely resistive circuit so there is no Q or power factor.
 

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