Ball thrown in the air, calculate time to hit the ground.

[T.J.12]

Hi everyone! First post here, seems like a great community. Anyways, I'm having a bit of trouble.

(I missed a bit of classes due to illness, and I'm a bit behind.)

Here's the problem:

You stand on top of a building 9.50 meters high, and throw a ball almost straight up. The ball is released with an initial velocity of 25m/s [up]. If you release the ball from 2.5m above the top of the building, find the time it takes for the ball to land on the ground.

Thanks in advance!

 

[LowlyPion]

Hi everyone! First post here, seems like a great community. Anyways, I'm having a bit of trouble.

(I missed a bit of classes due to illness, and I'm a bit behind.)

Here's the problem:

You stand on top of a building 9.50 meters high, and throw a ball almost straight up. The ball is released with an initial velocity of 25m/s [up]. If you release the ball from 2.5m above the top of the building, find the time it takes for the ball to land on the ground.

Thanks in advance!

Welcome to PF.

What have you tried so far?

 

[nlightner]

Hi there! Welcome to the community!

To calculate the time it takes for the ball to hit the ground, we can use the equation:

h = h0 + v0t - 1/2gt^2

Where:
h = final height (0m)
h0 = initial height (9.50m)
v0 = initial velocity (25m/s)
g = acceleration due to gravity (9.8m/s^2)
t = time

Plugging in the values given in the problem, we get:

0 = 9.50m + (25m/s)t - 1/2(9.8m/s^2)t^2

Solving for t using the quadratic formula, we get t = 3.25 seconds. This means that it takes 3.25 seconds for the ball to hit the ground.

I hope this helps! Let me know if you have any further questions. Keep up the good work!