A bullet (m = 0.0270 kg) is fired with a speed of 99.00 m/s and hits a block (M = 2.60 kg) supported by two light strings as shown, stopping quickly. Find the height to which the block rises. I found this by conservation of energy, the answer was .0528 m Find the angle (in degrees) through which the block rises, if the strings are 0.280 m in length. I tried doing this using trig. the hypotenuse= .280 m opposite = (.280-.0528) = .2272 m adjacent= x sin^-1 (.2272/.280)= 54.2 deg. What am I doing wrong?