Ballistics -- How deep does the bullet penetrate into the wood?

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SUMMARY

The discussion focuses on calculating the penetration distance of a bullet into wood using the formula d = mv² / 2C. The user provided values of mass (m = 20g), velocity (v = 300km/h), and frictional force (C = 750 N). The initial calculation yielded a penetration distance of approximately 0.0926 meters, but the user encountered an issue when submitting the answer with two significant figures as 0.093. It was concluded that the correct answer should be expressed in centimeters, which resolved the confusion.

PREREQUISITES
  • Understanding of basic physics concepts, specifically dynamics and friction.
  • Familiarity with unit conversions, particularly between meters and centimeters.
  • Knowledge of significant figures and their application in scientific calculations.
  • Ability to manipulate and apply equations in physics, such as d = mv² / 2C.
NEXT STEPS
  • Study unit conversion techniques, especially converting meters to centimeters.
  • Learn about significant figures and their importance in scientific reporting.
  • Explore more complex applications of the penetration formula in different materials.
  • Investigate the effects of varying mass and velocity on penetration depth in practical scenarios.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding projectile dynamics and penetration mechanics in materials.

duchuy
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Homework Statement
How deep in a tree would a mass m firearm projectile penetrate at velocity v0 if the frictional force between the projectile and the wood is C ?
Relevant Equations
d = mv^2 / 2C
Hi, I was given this exercice where I have to calculate the penetration distance, knowing that m = 20g, v = 300km/h and C = 750 N and I have to give the results with two significant numbers. I really thought that all I had to do was replace the values so I did :
d = (20.10^-3) x (300/3,6)^2 / 2x750 and I ended up with d = 0,0925925925...
But when I entered the answer with two significant figures = 0,093, the answer was wrong.
Please help me find me find my mistake thank you so much!
Sorry if i have misused any term, I translated this from french.
 
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duchuy said:
Homework Statement:: How deep in a tree would a mass m firearm projectile penetrate at velocity v0 if the frictional force between the projectile and the wood is C ?
Relevant Equations:: d = mv^2 / 2C

Hi, I was given this exercice where I have to calculate the penetration distance, knowing that m = 20g, v = 300km/h and C = 750 N and I have to give the results with two significant numbers. I really thought that all I had to do was replace the values so I did :
d = (20.10^-3) x (300/3,6)^2 / 2x750 and I ended up with d = 0,0925925925...
But when I entered the answer with two significant figures = 0,093, the answer was wrong.
Please help me find me find my mistake thank you so much!
Sorry if i have misused any term, I translated this from french.
It looks right. It might be two decimal places, rather than two significant figures. Or, the answer in cm?
 
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oh my god the answer is actually in cm, thank you so much! how'd you figure that out...?
 
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duchuy said:
oh my god the answer is actually in cm, thank you so much! how'd you figure that out...?
I'm clever with things like that!
 
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Likes   Reactions: berkeman, Steve4Physics and duchuy

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