# Basic Airflow Calculation Help

1. Oct 13, 2014

### Norgie

I have a basic airflow question and my mind is in the fog. I'm trying to find the air pressure at a known flow rate and orifice size but I'm having issues with the unit conversions. I'm using Bernoulli's equation Pressure = 1/2 x Air Density x Flow Rate/Area. My Flow Rate is in L/M and the area is CM2. The air density is in KG/M3. The area of the orifice is not round but square. Could anyone help me with the correct formula and unit conversions.

Thanks

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2. Oct 13, 2014

### Staff: Mentor

Welcome to PF!

We need more information to be able to adequately help: what kind of pressure are you trying to calculate (static/dynamic/differential?) And where are you trying to calculate it? And how do you know the incompressible flow equation is valid here; is this a low pressure/velocity situation?

3. Oct 13, 2014

### SteamKing

Staff Emeritus
Flow rate units should be written L/min to avoid confusion with using M to represent meters and minutes. In any event, change the flow rate to L/s by dividing L/min by 60.

1000 L = 1 m3

100 cm = 1 m, therefore 10,000 cm2 = 1 m2

You're on your own with a square orifice. Are you sure the orifice isn't 'square edged'?

4. Oct 13, 2014

### Norgie

I'm trying to find the dynamic pressure of an airflow at 60 LPM. I'm trying to calculate the air pressure on the inlet side of a variable orifice. The variable orifice is a diaphragm loaded by a coiled spring. As the diaphragm opens, the air vents out to atmosphere through a square slot at a known size. The larger the airflow the more the diaphragm opens.

5. Oct 13, 2014

### Staff: Mentor

These two sentences either constrain or contradict each other: it sounds like you have a flow regulaing device that uses a spring to maintain a near-constant pressure somewhere. But what pressure/where?

Are you looking for the dynamic pressure (or velocity pressure VP) inside the orifice? Is it regulated inside the orifice? If that were the case, there'd be nothing to answer: it would be constant at whatever pressure was specified by whomever designed the device.

Are you looking for the dynamic pressure somewhere else - upstream or downstream of the orifice? Then it would be set by the pipe size. A diagram showing exactly where you want to measure the VP and how the orifice spring behaves would help.

In either case, if we assume that the incompressible flow equation works, it is basically plug-and-chug from the information you already have. I'd say give it a try with what you have and we'll go from there.

6. Oct 13, 2014

### Norgie

Thank you for your reply and now I know I need to explain what I'm doing a little more. I'm trying to measure air flow through a variable orifice that is made of a spring material. Attached is a rough drawing of the device. Air flow enters the device at point A and pushes against the metal spring. The air is exhausted out the vent on the top. The faster the airflow the more deflection I get on the metal spring. I measure the deflection of the spring and correlate it to a calibrated airflow rate versus deflection. I'm trying to model the device through flow equations so I can compensate the effects of barometric pressure changes and temperature. I was starting with the formula as first described to determine the pressure required to move the metal flat spring at a given flow rate. The flow rates this device measures is 0 L/min to 900 L/min. I used the equation as first described but my numbers were not coming out correctly. Again, the formula is Pressure = 1/2 x Air Density x Flow Rate / Area of the open vent. My air density is in Kg/m3, Flow Rate is in L/min and Area is cm2. I'm not sure what units the Pressure will come out to be.

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7. Oct 13, 2014

Well first of all, the unites of $\dfrac{\rho Q}{2A}$ are not pressure if $Q$ is volumetric flow rate. Consider that the units of your equation are $\frac{[kg/m^3]\cdot[m^3/s]}{[m^2]} = \frac{kg}{m^2\cdot s}$, which is not the same as $[Pa] = \frac{[N]}{[m^2]} = \frac{[kg\cdot m]/[s^2]}{[m^2]} = \frac{kg}{m\cdot s^2}$.
The actual definition of dynamic pressure is $q = \frac{1}{2}\rho v^2 = \frac{\rho Q^2}{2A^2}$. You forgot to square the velocity.