Very beginner physics 1D motion question

Click For Summary
SUMMARY

The forum discussion addresses a physics problem involving two cars moving towards each other, initially separated by 275 meters. The smaller car, traveling at 25.0 m/s, has an acceleration that is 20.0% greater than that of the larger car, which is moving at 30.0 m/s. The correct magnitudes of acceleration were determined to be approximately -0.689 m/s² for the larger car and -0.827 m/s² for the smaller car, after correcting the sign of the acceleration relationship to reflect their opposite directions. The solution emphasizes the importance of correctly assigning signs to accelerations based on direction.

PREREQUISITES
  • Understanding of kinematic equations, specifically the equation (Vf)^2=(Vi)^2+2a(Xf-Xi)
  • Basic knowledge of motion concepts, including acceleration and velocity
  • Familiarity with the concept of relative motion in physics
  • Ability to manipulate algebraic expressions to isolate variables
NEXT STEPS
  • Study the implications of acceleration signs in one-dimensional motion problems
  • Learn more about kinematic equations and their applications in real-world scenarios
  • Explore the concept of relative motion and how it affects problem-solving in physics
  • Practice solving similar problems involving multiple objects in motion
USEFUL FOR

Students studying introductory physics, educators teaching kinematics, and anyone interested in understanding motion dynamics in one-dimensional scenarios.

mistymoon_38
Messages
18
Reaction score
0
[SOLVED] Very beginner physics 1D motion question!

Homework Statement


Two cars move in opposite directions toward each other on a level, straight, one-lane road. When both drivers begin to brake, their front bumpers are 275 meters apart. The smaller car is initially moving at 25.0 m/s and the larger is initially moving at 30.0 m/s. The magnitude of the acceleration of the smaller car is 20.0% greater than the magnitude of the acceleration of the larger. Determine the magnitude of acceleration for each car such that when their front bumpers touch, they have just come to rest



Homework Equations


(Vf)^2=(Vi)^2+2a(Xf-Xi)


The Attempt at a Solution


TRANSLATION:
1 stands for the larger car, 2 for the smaller car...
Xi1=0 Xi2=275
Xf1=unknown Xf2=unknown Xf1=Xf2
Vi1=30 Vi2=-25
Vf1=0 Vf2=0
a1=? a2=? a2=1.2a1

EQUATE:
0=(Vi1)^2+2a1(Xf1)
0=(Vi2)^2+2.4a1(Xf2-Xi2)

To solve for a1 I isolated Xf1 in the first equation and then plugged that in where Xf2 is on the second equation, since they are equal. I ended up with:

a1=((Vi2)^2-1.2(Vi1)^2)/(2.4Xi2)
a1= ((-25)^2-1.2(30)^2)/(2.4*275)
a1=-.689 m/s^2
and therefore
a2=-.827 m/s^2
which is the magnitude if you take the absolute value...

So I am wondering if this is correct becaue I am having difficulty verifying my answers and I'm not sure if this is reasonable..
 
Physics news on Phys.org
Hi mistymoon_38,

To check this problem you can use the accelerations you found to find the displacement that each car takes during their trip and see if the distances each travels adds up to 275 meters.

There's a subtle error in one of your expressions. You have set up the problem so that for each car the positive and negative directions are the same. However, the accelerations of the cars are in opposite directions (so one is negative and one is positive). So you cannot write a_2 = 1.2 a_1 because this forces both accelerations to have the same sign. If you use a_2 = -1.2 a_1 I believe you'll get the proper relationship between the accelerations.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 97 ·
4
Replies
97
Views
17K
  • · Replies 3 ·
Replies
3
Views
2K