Basic physics forces problem (f=ma)

In summary, a 28.0-kg block connected to an empty 1.00-kg bucket by a cord running over a frictionless pulley has a coefficient of static friction of 0.450 and a coefficient of kinetic friction of 0.320. When sand is gradually added to the bucket, the system just begins to move when the tension force equals the static friction force. This means that the mass of the sand added to the bucket is equal to the maximum static friction force and the acceleration of the system is zero. To produce a non-zero acceleration, the applied force would need to be increased by a infinitesimally small amount, equal to the mass of one grain of sand.
  • #1
victoration1
7
0

Homework Statement


A 28.0-kg block is connected to an empty 1.00-kg bucket by a cord running over a frictionless pulley. The coefficient of static friction between the table and the block is 0.450 while the coefficient of kinetic friction is 0.320. Sand is gradually added to the bucket until the system just begins to move. What is the mass of the sand added to the bucket and the acceleration of the system?

Homework Equations



F=ma

The Attempt at a Solution



The major assumption that the problem demands---and with which I have trouble understanding---is that static friction is overcomed the moment that tension force (pulling on the block) equals the static friction force (acting in the opposite direction as tension force). There should be zero net-force at this point, and knowing Newton's first law, the block shouldn't move at all.

Does kinetic friction take over the moment that static friction equals the tension force? (thus making this problem possible)
 
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  • #2
Suppose that the applied force is exactly equal to the maximum static friction force.

How much would the applied force have to be increased so that it would produce a non-zero acceleration?
 
  • #3
victoration1 said:
Does kinetic friction take over the moment that static friction equals the tension force? (thus making this problem possible)
The difference between not-yet-moving and starting to move is one grain of sand. :smile:
 
  • #4
The mass of the sand---the magnitude of the applied force---can be increased by a infinitesimally small amount to cause acceleration; thus allowing for the approximation of the mass that the question requires?
 
  • #5
Yes.
 

1. What is the formula for Newton's second law of motion?

The formula for Newton's second law of motion is F = m x a, where F represents force, m represents mass, and a represents acceleration.

2. How do you calculate the force required to move an object at a certain acceleration?

To calculate the force required to move an object at a certain acceleration, you can use the formula F = m x a, where F is the force in Newtons, m is the mass in kilograms, and a is the acceleration in meters per second squared.

3. What is the relationship between mass and acceleration in Newton's second law?

Newton's second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that as the mass of an object increases, the force required to accelerate it at a certain rate also increases.

4. How does Newton's second law relate to everyday experiences?

Newton's second law can be observed in everyday experiences, such as pushing a shopping cart or riding a bike. In these situations, the force applied determines the acceleration of the object. For example, pushing a heavier shopping cart requires more force to move it at the same acceleration as a lighter cart.

5. How can Newton's second law be applied to solve problems?

To solve problems involving Newton's second law, you can use the formula F = m x a and plug in the given values for force, mass, and acceleration. It is important to pay attention to the units used and make sure they are consistent throughout the calculation.

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