Bathroom scale being compressed but jumping on it

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Homework Help Overview

The problem involves a bathroom scale that compresses when a person stands on it, measuring their weight. The scenario includes a person jumping onto the scale from a height, and the question seeks to determine the scale's reading at the peak of the jump.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between force and spring compression, referencing Hooke's Law. They explore the conversion of gravitational potential energy to spring energy and attempt to calculate the spring constant and potential energy.

Discussion Status

The discussion is active, with participants sharing their attempts to solve the problem and asking clarifying questions. Some have provided guidance on relevant formulas and concepts, while others are still working through their understanding of the energy transformations involved.

Contextual Notes

Participants are navigating the problem with the constraints of homework rules, focusing on understanding the physics concepts without reaching a final solution.

kavipach
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Homework Statement


If you stand on a bathroom scale, the spring inside the scale compresses 0.55mm, and it tells you your weight is 760N.
Now if you jump on the scale from a height of 1.3 m, what does the scale read at its peak?
 
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What are your thoughts on the question? Post your attempt.
 
well i tried a few things... i found the persons mass which is 77.55kg.Since F=ma,and we have m, i tired using kinamatics to find a but finding the velocity of the person just before impact. Then i got stuck. I don't know how to go about this question.
 
kavipach said:
well i tried a few things... i found the persons mass which is 77.55kg.Since F=ma,and we have m, i tired using kinamatics to find a but finding the velocity of the person just before impact. Then i got stuck. I don't know how to go about this question.

So when the person stands on the scale, they weigh 760N. This means that the spring compresses. Do you know a formula that relates force and extension?
 
ya hookes law...F=kx.
 
where k equals spring constant and x equals displacment
 
kavipach said:
ya hookes law...F=kx.

yes

kavipach said:
where k equals spring constant and x equals displacment

good.


So can you find the spring constant,k using the information in the first line of the question?
 
according to this the constant equals to 1381818.2 is this right
 
kavipach said:
according to this the constant equals to 1381818.2 is this right

1381818.2 N/m yes, remember to put in your units.


So second line now. If the person is at 1.3m in the air, what type of energy does he have? This energy is converted into the energy needed to compress the spring a displacement,x, at the peak.
 
  • #10
potential energy?
 
  • #11
kavipach said:
potential energy?

yes. What is the formula for gravitational potential energy? And what is the formula for the energy stored by a spring?
 
  • #12
The formula for gravitational potential energy is U=mgy where u equals the p.e, m equals mass and y is the displacement. the formula for the energy storedd in a spring is U=1/2kx^2
 
  • #13
kavipach said:
The formula for gravitational potential energy is U=mgy where u equals the p.e, m equals mass and y is the displacement. the formula for the energy storedd in a spring is U=1/2kx^2

So if all the gravitational energy is converted to energy stored in the spring, that makes

gravitational p.e. = energy stored in the spring.


Can you find the compression,x for the scale now?
 
  • #14
ya i think i can..thanks for all the help..your a life saver
 

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