Beginner's Question Regarding Voltage Division

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The discussion focuses on understanding voltage division in a circuit, particularly for a beginner. The user calculates the voltage between points using Ohm's Law, confirming that voltage increases with resistance in a series circuit. It is clarified that voltage is a potential difference measured between two points, and the accuracy of voltage measurements depends on the reference points chosen. Additionally, it is emphasized that voltage dividers are not suitable for powering devices from higher voltage supplies, which is a common misconception among beginners. Overall, the conversation reinforces fundamental concepts of voltage division and measurement in electrical circuits.
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I'm pretty much a beginner trying to wrap my head around the concept of voltage division within a circuit. To help myself out, I've come up with the following circuit.

[PLAIN]http://img401.imageshack.us/img401/801/voltagedivision.gif

I am having trouble determining the voltage between various points on the circuit.

Starting with Ohms law, I know that the current in the circuit is 15V/15 ohms (or, 1A).

Given the current, I can now determine the voltage between various points of the circuit.


Between points 1 and 2, the amount of voltage is:

V=1A x 5 ohms=5V


Between points 1 and 3, the amount of voltage is:

V=1A x (5 ohms + 5 ohms)
V=1A x 10 ohms=10V

Is this correct? Does the amount of voltage actually increase as your resistance increase? Sorry for sounding like a complete noob (which I am :) )


Additionally, say I need to supply 10V to a device that happens to be connected at point 6 on my drawing. Where is the voltage measured from? Assuming I'm correct, if you measure from point 1 to point 6, then there is 10V being supplied. However, if you measure from point 2 to point 6, there is only 5V being supplied. Which figure is accurate?
 
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Your calculations seem correct.

Current passing through a resistance make the voltage drop.

For your last questions, I don't believe I follow you very well. Electric potential is always applied / measured between two points of a circuit. Therefore, it would be difficult to add 10V at point 6.

Cheers
 
Ulnarian said:
Is this correct?

In short... yes :)

Does the amount of voltage actually increase as your resistance increase?

The basic answer is... yes :)

Additionally, say I need to supply 10V to a device that happens to be connected at point 6 on my drawing. Where is the voltage measured from? Assuming I'm correct, if you measure from point 1 to point 6, then there is 10V being supplied. However, if you measure from point 2 to point 6, there is only 5V being supplied. Which figure is accurate?

Remember that voltage is always really a potential difference between two points; it's not absolutely defined at one point in a circuit.

What is the ground point in your circuit? Your device that you're connecting must have a ground, or "another side" to the circuit, where the current flows back out.

Also... remember that in practice voltage dividers aren't useful as power supply voltage regulators to power devices from a higher voltage supply than is appropriate... this is a common beginner mistake.
 
Here's a little interactive voltage divider you might like to play with.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/voldiv.html"
 
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