Behavior of charged particles in Free and Bound states

AI Thread Summary
In the discussion, the focus is on the attraction of a negative charge of 1 coulomb to three positive charges of +1, +3, and +5 coulombs positioned equidistantly. The conclusion is that the negative charge will be attracted to all three positive charges due to the fundamental principle of electrostatic attraction, which is governed by Coulomb's law, expressed as F = k * (q1 * q2) / r^2. The conversation also explores the differences in charge interactions when in "bound" states, such as in electrovalent compounds, versus "free" states, like suspended charged objects. In bound states, charges can neutralize each other, while in free states, the forces of attraction dictate behavior. Ultimately, the negative charge experiences attraction to all positive charges equally in a free state scenario.
petrushkagoogol
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If there are 3 positive charges of +1, +3, +5 coulombs equidistant from a negative charge of 1 coulomb what positive charge will this negative charge be attracted to ?

Is the result different if the charges exist in a “bound” state (resulting in electrovalent compounds) where a positive charge of +3 coulombs will be neutralized by a negative charge of (-)3 coulombs OR when the charges exists as suspended charged balls (similar to a pendulum) where the coulomb force of attraction determines the outcome.

This corresponds to a comparison of the behavior of charges when they exist in a “Free” or “Bound” state.
 
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petrushkagoogol said:
If there are 3 positive charges of +1, +3, +5 coulombs equidistant from a negative charge of 1 coulomb what positive charge will this negative charge be attracted to ?

All three, this is as trivial as \frac{q_1 q_2}{r^2}.
 
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