- #1

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The density of probability at the source is uniform it cannot depend on the measurement angles. Rho(v)

The measurement are made at the two places a(ta,v) b(tb,v)

The datas are the recollected at the same point.

In this last operation it is clear that the integration 'knows' about the measurement angles !

Hence the conclusion is that the correlation at the end should be written as [tex]\int_{\Omega[ta,tb]}a(ta,v)b(tb,v)\rho_{end}(ta,tb,v)[/tex] ?