Bernoulli's Equation to find a depth

awertag
Messages
63
Reaction score
0

Homework Statement



A perfectly spherical golf ball with a specific gravity of 0.55 is dropped from a height of 10 m above the surface of a smooth lake. Determine the maximum depth to which the ball will sink. Neglect any frictional loses or energy transferred to the water during impact and sinking.


Homework Equations



P=pressure ρ=density h or Y=depth g=9.8 Patmospheric=1.01e3 V=velocity

The Attempt at a Solution


I got velocity =14 m/s with free fall first. Then I did Bernoulli's.

P1 + ρgY1 + .5ρ(V1^2) = P2 + ρgY2 + .5ρ(V2^2)

1.01e3 + [STRIKE]ρg(0)[/STRIKE] +.5(550)(14^2) = (1000)(9.8)(h)+(550)(9.8)(h) + [STRIKE].5(ρ)(0)[/STRIKE]

54910 = (1000)(9.8)(h) +(550)(9.8)(h)

h = 3.6149 m




I would really really appreciate help! :)
 
Physics news on Phys.org
errr why do you think you have to use Bernoulli's equation here ? I don't think it has any application here.
 
Oh never mind, I got the answer. Thanks for replying though! :) have a great day
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top