Bessel's Equation and substitutions

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Homework Statement


Find a general solution in terms Jv of and Yv . Indicate
whether you could also J-v use instead of Yv. Use the
indicated substitution. Show the details of your work.

9x2y''+9xy'+(36x4-16)y=0

Substitution (z=x2)

Homework Equations



All given in part 1.

The Attempt at a Solution



Given z=x2, \frac{dz}{dx}=2x
Therefore \frac{dy}{dx}=\frac{dy}{dz}*\frac{dz}{dx}=2x*\frac{dy}{dz}

But I need the second derivative of y with respect to x to make the substitution, this is where I run into trouble. Using the chain rule, I get this:
\frac{d^{2}y}{dx^{2}}=2*\frac{dy}{dz}+\frac{d}{dx}(\frac{dy}{dz})*2x

I have no clue how to compute \frac{d}{dx}(\frac{dy}{dz})
Any help would be appreciated.
 
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For any function \phi, \frac{d\phi}{dx}= \frac{d\phi}{dz}\frac{dz}{dx}. In particular, if \phi= \frac{dy}{dz} then \frac{d}{dx}\left(\frac{dy}{dz}\right)= \frac{d^2y}{dz^2}\left(\frac{dz}{dx}\right)
 
Thank you!
 
i am also struggling with how I am going to compute
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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