Best fit value of eddy thermal diffusivity

AI Thread Summary
The discussion focuses on determining the best fit value of eddy thermal diffusivity (α) using a mathematical model for temperature as a function of depth and time. The model requires fitting temperature data from July 19th to the equation provided, which involves calculating α from the slope of a semi-log plot of T(y,t) - T0 versus y². Participants suggest using non-linear least squares fitting to minimize error in determining α and emphasize omitting data points where T(y,t) is less than T0 due to experimental uncertainty. The final approach involves calculating the slope from the plotted data and solving for α. This method provides a systematic way to analyze the temperature profile and derive the necessary diffusivity value.
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Homework Statement



A mathematical model for temperature T as a function of depth y (in m) and time t (in days) is:

(T(y,t)-T0)/(Tsurf(t)-T0)=e^(-y2/4αt) (2)where Tsurf(t) is the water temperature of the lake surface at time t, α is a property called the “eddy thermal diffusivity” and T0 is the lake temperature at time zero. Time zero must be chosen to be on a day when the lake temperature is more or less uniform.

Fit equation (2) to the data for July 19th to obtain the best fit value of α.

20-Dec 18-Apr 16-May 19-Jul
y (m) T(C) T(C) T(C) T(C)
0 10.8 19.1 22.2 28.4
1 10.7 18.7 21.8 27.9
2 10.5 18 21.4 28
3 10.5 17.4 21.2 27.9
4 10.5 17 21.1 27.4
5 10.5 16.4 20.7 26.2
6 10.5 16 19.3 23.6
7 10.5 15.2 17.1 21.4
8 10.5 14.7 15.6 19.3
9 10.5 13.7 14.6 17.9
10 10.5 12.9 14.1 16.8
11 10.5 12.1 13.2 15.9
12 10.5 11.6 12.7 15
13 10.5 11.1 12.1 14.1
14 10.5 10.7 11.6 13.2
15 10.4 10.4 11.3 12.4
20 10.3 9.3 9.9 10.6
25 10.3 8.9 9.4 9.8
30 10.1 8.7 9.1 9.3
35 10.3 8.7 8.8 9.1

Homework Equations


T0=10.5
t=211 since Dec. 20th is t=0

The Attempt at a Solution


I solved for α which gives the equation -y^2/[844ln(T - 10.5)/17.9]

so I started going down the list using the values from July 19th which gave me a different value for every value of T but once i got to T=9.8 I couldn't get any value for alpha because it would be the ln of a negative number... my question is how exactly should I look for the best fit value of α? is it the average value of the ones I was able to calculate? Or maybe I am missing something? Any help would greatly be appreciated.
 
Last edited:
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Sorry, here is a better look at the Temperatures from July 19th

19-Jul
T(C)
28.4
27.9
28
27.9
27.4
26.2
23.6
21.4
19.3
17.9
16.8
15.9
15
14.1
13.2
12.4
10.6
9.8
9.3
9.1
 
You probably want to do a non-linear least squares fit to the data, minimizing the error with respect to the eddy diffusivity.
 
Chestermiller said:
You probably want to do a non-linear least squares fit to the data, minimizing the error with respect to the eddy diffusivity.

Im not quite sure how I would go about doing that; but thanks for the reply.
 
Make a plot of T(y,t)-T(0) vs y2 on a semi-log plot, including only the points for which T(y,t) > T(0). The semi-log parameter should be T(y,t) - T(0). You should get something close to a straight line. The slope of this line should be -1/(4αt). Draw your best straight line in, and then calculate the slope. The points where T(y,t) < T(0) are omitted because, within experimental uncertainty, they are essentially equal to T(0).
 
so once I have the slope just solve for α?
 
Yes.
 

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