Billiard collision with same angle

  • Thread starter Thread starter madman143
  • Start date Start date
  • Tags Tags
    Angle Collision
AI Thread Summary
In the discussion, participants analyze a billiard problem involving a perfectly elastic collision between a cue ball and a 9-ball. The cue ball strikes the 9-ball off-center, causing both balls to move away at the same angle post-collision. Key principles include the conservation of momentum in both x and y directions, as well as the conservation of kinetic energy. One contributor notes the need to derive equations based on these conservation laws to solve for the angles and speeds involved. The conversation emphasizes the importance of applying physics principles correctly to determine the outcome of the shot.
madman143
Messages
11
Reaction score
0

Homework Statement



Jeanette is playing in a 9-ball pool tournament. She will win if she sinks the 9-ball from the final rack, so she needs to line up her shot precisely. Both the cue ball and the 9-ball have mass , and the cue ball is hit at an initial speed of . Jeanette carefully hits the cue ball into the 9-ball off center, so that when the balls collide, they move away from each other at the same angle from the direction in which the cue ball was originally traveling (see figure). Furthermore, after the collision, the cue ball moves away at speed , while the 9-ball moves at speed . (Intro 1 figure)

For the purposes of this problem, assume that the collision is perfectly elastic, neglect friction, and ignore the spinning of the balls.

pic attached

Homework Equations


v final=v

i get theta=cos^-1(v intial/2v)

please help. no numericals were given in this problem?
 

Attachments

  • 9ball.jpg
    9ball.jpg
    5.8 KB · Views: 726
Physics news on Phys.org
First of all figures that Jeanette would choke on the money ball. But that said, don't you also need to conserve kinetic energy as well?
 
you've got conservation of momentum along the x direction and along the y direction, see if you can throw those two equations down, then throw down one more with conservation of energy.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top