Binomial Theorem Proof: (nC0)(mC0) + (nC1)(mC1) + ... + (nCm)(mCm) = (n+m C m)

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Homework Statement



To Prove:
(nC0)(mC0) + (nC1)(mC1) + ... + (nCm)(mCm) = (n+m C m)

where nC0 = n choose 0 and so on.

Homework Equations





The Attempt at a Solution


Tried expanding the whole thing using factorials - but didn't work. Any hints would be really welcome!
 
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You should review proof by induction and then try to apply it here.
 
Do I do induction on m?? So that would mean , that by assumption ...+(nCm)(mCm) = (n+m C m)...then to prove ...+(nCm+1)(m+1Cm+1) = (n+m+1 C m+1) ...correct?
 
Yes, that should work.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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