Biot-Savart Law for a Point Charge

AI Thread Summary
The discussion focuses on deriving the magnetic field (B) for a point charge using the Biot-Savart Law. The user describes a scenario where a point charge moves at a constant speed along the x-axis, creating a circular path at a distance R. They plan to calculate the electric flux due to the charge and note that the symmetry ensures B remains constant along the path. The user expresses uncertainty about their setup and seeks confirmation before proceeding further. The conversation emphasizes the importance of manipulating the equations to eliminate the cross product in the calculations.
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Homework Statement



Show that B for a point charge is equal to

6bb1d60bd48bb83ace488aa5e7b87cdf.png


Homework Equations



I'm not all that sure. I read that maxwell's equations can be used to derive this, so I'd imagine that it's

1c88050c83555c51feb62402559d6cae.png



The Attempt at a Solution



If it were that, then, if i have a point charge moving at some constant speed along the x-axis and I wanted to find B some distance R from it, at that point, I would create a circular path a distance x from the charge with radius R. I can find the electric flux due to the point charge throughout the entire circular disk. Because its moving with constant speed, i can find x(t) which is equal to vt setting my initial location for the charge at x = 0. Also because of the symmetry, B must be the same along the entire path since the charge is the same distance from every point on the path.

So, the flux as a function of the distance from the point charge is as shown in the picture below

http://img707.imageshack.us/img707/6956/itsazoo.png

Now that equation really does NOT look like it's going to go anywhere productive so I want to ask if my concepts/setup are right before going any further.
 
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Keep going. Don't give up. Eventually, you will get the Biot-Savart Law.

(However, remember that you have to get rid of the cross product somehow. v cross r-unit is equal to vsin(theta) in magnitude, so substitute that to get rid of the vectors.)
 
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