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Bisection method

  1. Jan 19, 2017 #1
    1. The problem statement, all variables and given/known data
    In the first photo , interval [-2 ,2 ] means a = -2 , b = 2 , am i right ?
    So , how to show that b-a = 1 ?

    2. Relevant equations


    3. The attempt at a solution
    IMO , b-a = 2+ 2 = 4

    for part b , why b - a = -1-(-2) ?
    Is there anything wrong with this question ?
     

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  2. jcsd
  3. Jan 19, 2017 #2

    BvU

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    Not so: b and a play different roles.
     
  4. Jan 19, 2017 #3

    fresh_42

    Staff: Mentor

    ##[-2,2]## is the interval for which the functions are considered.
    The exercise suggests to apply the bisection method on another interval, namely ##[-2,-1]## because you don't need to consider the entire range. For the second question ##|b-a|=|-1-(-2)|=|1|=1##.
     
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