# Bisection method

1. Jan 19, 2017

### fonseh

1. The problem statement, all variables and given/known data
In the first photo , interval [-2 ,2 ] means a = -2 , b = 2 , am i right ?
So , how to show that b-a = 1 ?

2. Relevant equations

3. The attempt at a solution
IMO , b-a = 2+ 2 = 4

for part b , why b - a = -1-(-2) ?
Is there anything wrong with this question ?

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2. Jan 19, 2017

### BvU

Not so: b and a play different roles.

3. Jan 19, 2017

### Staff: Mentor

$[-2,2]$ is the interval for which the functions are considered.
The exercise suggests to apply the bisection method on another interval, namely $[-2,-1]$ because you don't need to consider the entire range. For the second question $|b-a|=|-1-(-2)|=|1|=1$.