Graphical Method for Determining BJT Inverter Characteristics

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The discussion focuses on using the graphical method to determine output characteristics for a BJT inverter. The user is struggling with the application of the load line on the transistor characteristic curves. Key equations provided include Vout = 4.5 - 1.5Ic and Vin = 45Ibase + 0.65, which are essential for plotting the Vout/Vin curve. By selecting values for Ibase and finding their intersection with the load line, the corresponding Ic values can be determined. The guidance aims to clarify the process and assist in successfully plotting the required characteristics.
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Hi I'm having some problems with using the graphical method to determine the output characteristics, the question and the answer are all included in the document attached. I understand the process of putting the load line on the graph but for this application i have no idea what to do.

Many thanks!
 

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Here are some hints:

Since we are working in milliamps use resistors in kohms.

Vout = 4.5 - 1.5Ic

Vin = 45Ibase+0.65

So chose a series on Ibase and note where your load line intersects that value on the transistor characteristic curves graph.
Move across the graph horizontally from this intersection to read off the value of Ic corresponding to that value of Ibase

Substitute these pairs of values into the above equations to plot the Vout / Vin curve, as far as the noise limits given.

Does this help?
 
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