Help Input output characteristics of BJT

In summary: For a pnp transistor, the active mode would be when Vcb<0. In summary, the conversation discusses the input-output characteristics of BJT and how they differ for npn and pnp transistors. The graph provided in the link only applies for npn transistors, and for pnp transistors, the active region would be when Vcb<0. The conversation also includes a link to a blog post that further explains the topic.
  • #1
iampaul
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help! Input output characteristics of BJT

I have attached an image of the graph. Does this graph apply for both npn and pnp transistors. I have asked this because for pnp, the collector(c) and base(B) terminals must be reverse-biased at the active region, and B must be at a higher potential than C. Therefore, i think that for the active region Vcb is negative: Vcb= Vc-Vb <0 so Vbc must be positive. As shown in the graph, the transistor is in the active mode for Vcb>0. Why?

For npn there is no problem. That's why I'm asking whether this graph applies for both npn and pnp. Please reply. Thanks!
 
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  • #2


i can't attach the pic so i'll jusr give the link
http://comutronics.blogspot.com/2012/02/ece-basic-interview-question-and_06.html
 
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  • #3


iampaul said:
I have asked this because for pnp, the collector(c) and base(B) terminals must be reverse-biased at the active region, and B must be at a higher potential than C. Therefore, i think that for the active region Vcb is negative: Vcb= Vc-Vb <0
Correct for a pnp transistor.

As shown in the graph, the transistor is in the active mode for Vcb>0. Why?
Presumably because they are showing the graph for a npn transistor.
 
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