Block launching off ramp given initial velocity and Friction

AI Thread Summary
A block on a 35-degree ramp, 5 meters long, is given an initial velocity of 12 m/s and experiences static and kinetic friction coefficients of 0.6 and 0.2, respectively. The main challenge is determining the final velocity as the block exits the ramp, with attempts yielding incorrect results around 8.57 m instead of the expected 9.75 m. The equation used for calculating final velocity incorporates gravitational potential energy and frictional forces but needs clarification on how to apply static friction. The discussion emphasizes the need to accurately integrate friction into the calculations to find the exit velocity and subsequently the distance traveled after leaving the ramp. Understanding the dynamics of the block's motion and friction is crucial for solving the problem correctly.
physicN00Bz
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Homework Statement



a block is at the base of a ramp of angle 35degrees. The ramp is 5 m long and has a coefficient of static and kinetic friction of .6 and .2 respectively. The block is initially given a velocity of 12 m/s up the ramp, how far from the ramp will the block land?

my main problem is finding the final velocity as the block exit the ramp, honestly i really don't know where to start.

Homework Equations


to find the final velocity of the block exiting the ramp i use

0.5 * m * v^2 = m * h * g + m * g * cos (theta) * Kf * L + 0.5 * m * V^2


The Attempt at a Solution



The answer is 9.75 m, all of my answer come out to be 8.57m or something close, what am i doing wrong? how do i applied the static friction into the equation?
 
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physicN00Bz said:
to find the final velocity of the block exiting the ramp i use

0.5 * m * v^2 = m * h * g + m * g * cos (theta) * Kf * L + 0.5 * m * V^2

This equation gives the final speed the block leaves the ramp. How do you proceed to get the the distance from the ramp the block will land?

ehild
 
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