Block on a ramp problem - energy

AI Thread Summary
The discussion centers on calculating the initial velocity of a package projected up a 15º incline with a coefficient of kinetic friction of 0.12. The height at the top of the ramp is determined to be 2.588m. A participant initially misapplies the work-energy principle by incorrectly including potential energy in their calculations. It is clarified that potential energy should not be counted twice, as it already accounts for the work done by gravity. The importance of including the distance in the work terms is emphasized to arrive at the correct solution.
Marioqwe
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Homework Statement



Package is projected 10 m up a 15º incline so that it justreaches the top of the incline with zero velocity. μk =0.12

a) Determine initial velocity of package at A

Homework Equations



Energy and friction equations

The Attempt at a Solution



Height at the top of ramp h = 2.588m

Work = change in energy

W = -μmgcos(15) - mgsin(15) = mgh - 0.5mv^2

But I get the wrong answer. Am I supposed to use potential energy? and if not why not?

Thanks
 
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Marioqwe said:
W = -μmgcos(15) - mgsin(15) = mgh - 0.5mv^2

But I get the wrong answer. Am I supposed to use potential energy? and if not why not?
(1) If you include potential energy, that automatically takes care of the work done by gravity. Don't count it twice.
(2) The work terms must be of a form force*distance. You left out the distance.
 
I see my mistake. many thanks Doc Al.
 
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