Body suspended from a linear spring

In summary, the problem asks to find the angular frequency of vertical oscillations when two springs are used together in parallel. The hint provided suggests calculating the restoring force for each case. For the parallel case, the total restoring force is simply the sum of the individual forces from each spring. The next step would be to find the effective spring constant and effective angular frequency. In the series case, the bodies would be in line with each other and share an attached spring, with the next step being to find the individual restoring forces and then the effective spring constant and effective angular frequency.
  • #1
Benzoate
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Homework Statement



When a body is suspended from a fixed point by a certain linear spring, the angular frequency of the vertical oscillations is found to be [tex]\Omega[/tex]1. When a different linear spring is used, the oscillations have angular frequency . [tex]\Omega[/tex]2. Find the angular frequency of vertical oscillations when two springs are used together in parallel.

Here is a link to the problem that provides hints to the problem: http://courses.ncsu.edu/py411/lec/001/: Go to the Homework section of the webpage, then go to assignment 5, then go to problem 5.2.

Homework Equations



F=k*eff*[tex]\Delta[/tex] x
[tex]\sqrt{k*eff/m}[/tex]=[tex]\Omega[/tex]



The Attempt at a Solution



The hint to the problem says I need to calculate restoring force for each cases.

For the parallel case, would each of the two springs exert a contact force on each other since both bodies would be attached to two different springs?

For the series case, both bodies would be in line with each other; would body would behind or in front of the other body, while sharing an attached spring; therefore I know that there is definitely

[tex]\sqrt{k*(1)/(m)}[/tex]=[tex]\Omega[/tex]1 ==>

[tex]\Omega[/tex]1^2=[tex]k*1/m}[/tex]
[tex]\Omega[/tex]2^2=[tex]k*2/m}[/tex]

F1= ([tex]\Omega[/tex]1^2)*m*[tex]\Delta[/tex] x
F2= ([tex]\Omega[/tex]2^2)*m*([tex]\Delta[/tex] x)

Not sure what my next step should be after that
 
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  • #2
anyone have a hard time reading my post?
 
  • #3
If the springs are attached in parallel, then the total restoring force is just [itex]F=F_1+F_2=k_{eff}\Delta x[/tex]. So what does that make [itex]k_{eff}[/itex]? How about [itex]\Omega_{eff}[/itex]?

P.S. subscripts and superscripts in LaTeX are just A_{whatever} and A^{whatever}
 

1. What is a body suspended from a linear spring?

A body suspended from a linear spring is an object that is attached to a spring and is allowed to move freely under the influence of gravity and the spring's restoring force.

2. What factors affect the motion of a body suspended from a linear spring?

The motion of a body suspended from a linear spring is affected by the mass of the object, the spring constant of the spring, and the initial displacement of the object from its equilibrium position.

3. How does the spring constant affect the motion of a body suspended from a linear spring?

The spring constant determines the stiffness of the spring and how much force is required to stretch or compress it. A higher spring constant will result in a faster oscillation of the body suspended from the spring.

4. What is the equilibrium position for a body suspended from a linear spring?

The equilibrium position for a body suspended from a linear spring is the point where the spring is neither stretched nor compressed and there are no external forces acting on the object.

5. How does the mass of the object affect the period of oscillation for a body suspended from a linear spring?

The period of oscillation for a body suspended from a linear spring is directly proportional to the square root of the mass of the object. This means that a heavier object will have a longer period of oscillation compared to a lighter object on the same spring.

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