Boiling point at a certain pressure

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SUMMARY

The discussion centers on calculating the boiling point of a liquid at pressures different from standard temperature and pressure (STP). The ideal gas equation, represented as (PV)/T=(P'V')/T', is deemed inappropriate for this purpose. Instead, the Clausius-Clapeyron equation is identified as the correct approach, as it specifically addresses vapor-liquid equilibrium thermodynamics. The challenge lies in determining the heat of vaporization required for the Clausius-Clapeyron equation.

PREREQUISITES
  • Understanding of the Clausius-Clapeyron equation
  • Knowledge of vapor-liquid equilibrium thermodynamics
  • Familiarity with the concept of heat of vaporization
  • Basic grasp of standard temperature and pressure (STP) conditions
NEXT STEPS
  • Research the Clausius-Clapeyron equation in detail
  • Learn methods to calculate heat of vaporization for various substances
  • Explore vapor-liquid equilibrium concepts and their applications
  • Study the limitations of the ideal gas law in thermodynamic calculations
USEFUL FOR

Chemists, chemical engineers, and students studying thermodynamics who are interested in phase changes and vapor-liquid equilibrium calculations.

kthouz
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How can one calculate the boiling of a liquid at a pressure different from standard temperature?

Am trying to do it using the ideal gas equation,

(PV)/T=(P'V')/T'
Where P is the STP, V is 22.4l, T= boiling point at STP, P'= new pressure, V' is the new volume and T' is to be found. But is it easy to find V'.

But I found another equation of Clausius-Clapeyton which involves the heat of vaporisation. Using this equation, the problem is finding the heat of vaporisation. Can anyone help me?
 
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The ideal gas law is the wrong equation to use (since it has nothing to do with vapor-liquid equilibrium) but the Clausius-Clapeyron equation is the correct equation to use (since it is derived by specifically focusing on vapor-liquid equilibrium thermodynamics).
 

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