Bouncing Steel Ball (Elastic Collision)

AI Thread Summary
The discussion revolves around the physics of a 35 g steel ball that bounces elastically on a steel plate, consistently reaching a height of 20.8 m. The initial speed of the ball upon leaving the plate is calculated to be approximately 20.199 m/s. Participants explore the change in momentum during bounces, with the conclusion that the total change in momentum is approximately 1.41 J, factoring in the direction of velocity. The time interval between bounces and average force exerted by the ball are derived using kinematic equations, while the weight of the ball is clarified as simply being its mass multiplied by gravity. Overall, the conversation emphasizes the application of conservation laws and kinematics in solving the problem.
Awwnutz
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http://img395.imageshack.us/img395/6158/steelballxu7.gif

A 35 g steel ball bounces elastically on a steel plate, always returning to the same maximum height h = 20.8 m.

a) With what speed does the ball leave the plate?

b) What is the magnitude of the total change in momentum of the ball with each bounce?

c) What is the magnitude of the total momentum the ball transfers to the plate at each bounce?

d) What is the time interval between bounces?

e) Averaged over a long time interval, what is the magnitude of the rate at which momentum is transferred to the plate?

f) What is the magnitude of the average force exerted by the ball on the plate?

g) What is the weight of the ball?



Conservation of energy and momentum i believe will have to be used here.


I figured out part a.)
I set the Kinetic energy equal to the work done by gravity and found the ball moves at 20.199 m/s.

It's part b.) that I'm having the problem with. I initially thought the magnitude would have to be zero since the ball would have to moving at the same speeds to continue reaching the same height. But now i feel that it will have to be moving faster coming back up because it will counteract gravity whereas when its moving down it's moving with gravity. I just can't figure out a way to put that into an equation.
 
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Awwnutz said:
http://img395.imageshack.us/img395/6158/steelballxu7.gif

A 35 g steel ball bounces elastically on a steel plate, always returning to the same maximum height h = 20.8 m.

a) With what speed does the ball leave the plate?

b) What is the magnitude of the total change in momentum of the ball with each bounce?

c) What is the magnitude of the total momentum the ball transfers to the plate at each bounce?

d) What is the time interval between bounces?

e) Averaged over a long time interval, what is the magnitude of the rate at which momentum is transferred to the plate?

f) What is the magnitude of the average force exerted by the ball on the plate?

g) What is the weight of the ball?



Conservation of energy and momentum i believe will have to be used here.


I figured out part a.)
I set the Kinetic energy equal to the work done by gravity and found the ball moves at 20.199 m/s.

It's part b.) that I'm having the problem with. I initially thought the magnitude would have to be zero since the ball would have to moving at the same speeds to continue reaching the same height. But now i feel that it will have to be moving faster coming back up because it will counteract gravity whereas when its moving down it's moving with gravity. I just can't figure out a way to put that into an equation.

In b) they are asking for ΔM. What is that if it reverses upon striking the plate? Remember V is a vector.
 
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The change in momentum?

The vector as the ball moves downward would be negative, but as it bounces and begins to move upward it would then be positive.
 
the momentum of the ball moving back up would be (.035kg * 20.199m/sec) = .706965J

-.707 - .707 = 1.41J total. Ok got it.
 
Now I'm on to the time interval between bounces. Would i just use 2-D Kinematics?
 
1-D dynamics will do...
 
Alright i figured that one out.

I'm stuck on finding the weight of the ball...what equation would i want to do to find that?

Should i set the change in Kinetic energy = the work done by gravity to find the mass?
 
Awwnutz said:
Alright i figured that one out.

I'm stuck on finding the weight of the ball...what equation would i want to do to find that?

Should i set the change in Kinetic energy = the work done by gravity to find the mass?

You might do better to work it out as the variables.

For instance the Δp (change in momentum) is as you have already found 2*m*v. where:

v = (2*g*h)1/2

Now the average Force then is Total force over ΔT which is the period you found.

And T you can find from h = 1/2*g*t2. But you have to double it for the time up and then down again

T = 2*t = 2*(2h/g)1/2

Hence ΔT = 2*(2h/g)1/2

So ... Favg = Δp/ΔT = 2*m*v/ 2*(2h/g)1/2

But what did we find the Velocity could be expressed as? Try substituting that into this equation.
 
Awwnutz said:
Alright i figured that one out.

I'm stuck on finding the weight of the ball...what equation would i want to do to find that?

Should i set the change in Kinetic energy = the work done by gravity to find the mass?

Huh? The mass is given.
 
  • #10
borgwal said:
Huh? The mass is given.

I think that the idea is to show a derivation of weight.
 
  • #11
LowlyPion said:
I think that the idea is to show a derivation of weight.

I know, but the poster thinks he needs to find the mass.
 
  • #12
Yeah i definitely overlooked what i was given. They give me the mass and all i needed to do was find the weight. I start doing all these equations and formula's that i figure everything needs to be some type of formula so i overlook something so simple. I feel like an idiot :)

Thanks for all the help everyone!
 
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