Break a Stick Example: Random Variables

ashah99
Messages
55
Reaction score
2
Homework Statement
Provided below in the comments
Relevant Equations
f(x,y) = f(y|x)f(x)
Law of iterated expectation: E[ Y ] = E( E(Y|X) )
Hello, I would like to confirm my answers to the following random variables question. Would anyone be willing to provide feedback and see if I'm on the right track? Thank you in advance.

1663188804733.png

My attempt:

1663189296923.png
 
Physics news on Phys.org
You have not explained your choice of integration limits in (a), and I think the set-up of the integral is wrong.
One usually approaches problems like this by calculating a formula for the cumulative probability function ##F_Y(y) = Prob(Y\leq y)##, and then calculating the PDF as ##f_Y(y) = \frac d{dy} f_Y(y)##. Only in very simple cases can you skip these steps and go directly to the PDF.
The formula for ##F_Y(y)## will be a double integral over ##x\in(0,1)## and ##u\in[0,\min(x,y)]##. To start, draw a diagram of the integration region on an x-u plane. You will see that the region has a trapezium shape, so you will need to break the inner integral into two parts.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top