Bringing a derivative inside an integral?

[AxiomOfChoice]

I'm trying to show that a function f(z) is analytic by showing f'(z) exists. But f(z) is defined in terms of a contour integral:
<br /> f(z) = \oint_{|\zeta - z_0| = r} g(z,\zeta) d\zeta.<br />
Since the integral is being carried out with respect to \zeta and not z, am I allowed to bring the d/dz operator inside the integral? Or is it more complicated than that? Are there certain conditions that g(z,\zeta) must satisfy? If so, what are they?

THANKS!

 

[Gib Z]

I'm not sure if it will work the same for Contour Integrals, but the conditions for bringing a derivative inside are given nicely here: http://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign

 

[Phyisab****]

I think you might want to use leibnitz rule.