Bucket hanging on a rope(Tension)

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A bucket weighing 200N is suspended from a rope between two trees forming a 120-degree angle. The tensions in the ropes are equal, and each rope makes a 60-degree angle with the vertical. To find the tension, the component method of vector addition is recommended, focusing on the vertical components that must sum to balance the downward force of 200N. The equations F=ma and the component breakdown for both x and y directions are essential for solving the problem. The discussion emphasizes the importance of correctly applying these principles to arrive at the solution.
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Homework Statement


A bucket full of water weighs 200N. it is hanging from a rope tied between two trees. They form an angle of 120* with each other. The tensions are equal.


Homework Equations


F=ma
Rx=Ax+Bx+Cx
Ry=Ay+By+Cy
R=[(Rx)^2+(Ry)^2]^(1/2)

What's the tension in each rope?



The Attempt at a Solution



Should I use the component method of vector addition here? I'm in a dead end. I tried the component method but don't know if th angle is negative or positive, and I'm also not sure if the the resultant that I would find would be the correct answer.
 
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You haven't shown enough work for anyone to help you yet. But, yes, use the component method. Since the tensions in each rope are equal and there is 120 degrees between them you can assume each makes an angle of 60 degrees from the vertical. There is a 200N force downward and the vertical components of the tensions must sum to cancel that. Take it from there.
 
You should assume this

F=ma

where a = Zero

so...F= Zero

then you have to get the x and y components of each tension and do your equations...the rest is simple math
 

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