Buckling and column effective length question

AI Thread Summary
The discussion focuses on calculating the minimum length of a fixed column where buckling is likely to occur, given specific dimensions and material properties. The user calculated the effective length using the equations for K and ESR, arriving at a minimum length of 6.84 meters. The calculations involved determining K from the outer and inner diameters, and ESR from Young's modulus and yield stress. The final result was confirmed as correct by another participant in the discussion. The calculations demonstrate the application of structural engineering principles to assess buckling in columns.
fuofa
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Homework Statement


If I have a column, fixed at both ends, i am aiming to work out the minimum length where buckling is likely to occur.
I know this is a similar question to that asked before, however please bear with me.
Column outer diameter 100mm, inner diameter 60mm
Youngs modulus E=250GNm^-2
Yield stress = 180MNm^-2

Homework Equations


1. K = 0.5 sqrt (R^2 + r^2)
2. ESR = sqrt pi^2 E/ yield stress
3. ESR = Le/k

The Attempt at a Solution



To find K using the above equation I have taken the radius 0.5 x sqrt (0.05^2 + 0.03^2) = 0.0292
Then to find the ESR I have sqrt(pi^2 x 250000000000 / 180000000) = 117.080
Changing the third equation from above for Le I have ESR x K = Le (117.080 x 0.0292) = 3.419m
Given that the column is fixed at both ends I have multiplied this by 2 and reach the minimum length of the column at which buckling is likely to occur to be 6.84 m - is that correct please?
 
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fuofa said:

Homework Statement


If I have a column, fixed at both ends, i am aiming to work out the minimum length where buckling is likely to occur.
I know this is a similar question to that asked before, however please bear with me.
Column outer diameter 100mm, inner diameter 60mm
Youngs modulus E=250GNm^-2
Yield stress = 180MNm^-2

Homework Equations


1. K = 0.5 sqrt (R^2 + r^2)
2. ESR = sqrt pi^2 E/ yield stress
3. ESR = Le/k

The Attempt at a Solution



To find K using the above equation I have taken the radius 0.5 x sqrt (0.05^2 + 0.03^2) = 0.0292
Then to find the ESR I have sqrt(pi^2 x 250000000000 / 180000000) = 117.080
Changing the third equation from above for Le I have ESR x K = Le (117.080 x 0.0292) = 3.419m
Given that the column is fixed at both ends I have multiplied this by 2 and reach the minimum length of the column at which buckling is likely to occur to be 6.84 m - is that correct please?

Yes, this looks correct.
 
Thank you!
 
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